class VI activity- h.c.f,Integers

Objective: To find the h.c.f (highest common factors) of the given numbers experimentally through paper cutting and pasting.
Previous knowledge: 1. Factors of numbers
2. division of numbers

Material required: A rectangular strip of 36 cm in length and 2cm in width
A rectangular strip of 28 cm in length and 2cm in width
A pair of scissiors
fevicol
scale
procedure:
1.The first two strips represent numbers 12 and 20.Finding H.C.F means finding highest common factorof 12 and 24. that is, finding that biggest length of the strip which measures the length of 12 and20 exactly.





2. here from the first two strips it is clear that length can not be 12cm as 12 does not divide 20 and 12 exactly.
3. If we keep the first strip of 12 cm along 20 cm, we observe that length of the strip 8cm is left out in the second strip of 20cm.
20 / 12 leaves the remainder as 8.



4. We also observe that the length can't be 8 cm as it does not divide 12cm and 20 cm exact number of times.
5.now, on dividing, 12 with 8 (12/8) we see that the remainder is 4

6.the strip of 4cm divides cm exactly.
7.Thus we see that 4cm long strip divides 12 cm and 24cm exactly.

Result: the H.C.F of 20 cm and 12 cm is 4.
Assignment : Try the same activity for 36 and 28 cm.


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classVI(Integers)

Objective: Addition of two numbersexperimentally through paper cutting and pasting.
Previous knowledge: On addition of a positive integer to its negative integer gets nullified (or zero).
Procedure:
step 1: Firstly cut 25 unit squares which are kept unshaded and call them positive squares.
step 2: Then cut 25 unit squares which are kept shaded and call them negative squares.
step 3: case 1: Now, take (+8) + (+7)
we take 8 positive squares and 7 positive squares
count them (+8) + (+7) = 15
step 4: Case 2: now take,(-4) + (-5)
we take 4 negative squares and 5 negative squares
count them (-4) + (-5) = -9
Step 5: Case 3:Now take (+6) + (-5)
we take 6 positive squares and 5 negative squares
Count them (+6) + (-5) =1
Step 6: Case 4: Now take (-5) +(3)
we take 5 negative squares and 3 positive squares
Count them (-5) + (+3) = -2
Result:(i) If both the integers are positive then we add and the result is an positive integer.
(ii) If both the integers are negative then we add and the result is an negative integer.
(iii) If positive integer is greater than the negative integer then we subtract and the result is an positive integer.
(1v) If negative integer is greater than positive integer then we subract and the result is an negativ integer.
her sand
Assignment: -8 + 6 =
-4 - 5 =